0.01x^2+0.1x+3=0

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Solution for 0.01x^2+0.1x+3=0 equation: 



0.01x^2+0.1x+3=0

a = 0.01; b = 0.1; c = +3;
Δ = b2-4ac
Δ = 0.12-4·0.01·3
Δ = -0.11
Delta is less than zero, so there is no solution for the equation

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